Find the valuer of a if x+6 is a factor of x3+3x2+4x+a

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Ley p (x) = x3 + 3x​2 + 4x +a
Since, ( x+6 ) is a factor of p (x), then
  p (-6 ) = 0
           = ( -6 )3 + 3( -6 )2 + 4( -6 ) + a = 0
         =  -216 + 108 - 24 + a = 0
        =  -132 + a = 0
        =  a = 132
       
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