hey here's a question

the remainder obtained on dividing a polynomial p(x) by(x-1) is -5 and the qoutient is 3(x)3-(x)2-x-4. find p(x)

We know that,

Dividend = Divisor × Quotient + Remainder

 Here, the dividend is polynomial p(x) which we have to calculate, quotient is 3x3 - x2 - x - 4, divisor is (x - 1) and remainder is -5.

So, p(x) = (x - 1) × (3x3 - x2 - x - 4) + (-5)

= 3x4 - x3 - x2 - 4x - 3x3 + x2 + x + 4 - 5 

= 3x4 - 4x3 - 3x  - 1

Hence, p(x) = 3x4 - 4x3 - 3x  - 1, is the required polynomial.  

  • -1

p(x)=[3(x)3-(x)2-x-4] * (x-1) + (-5)

p(x)= (x-4/3)*(x-1)+(-5)

p(x)=3x2-7x-11 divided by 3

p(x)= x2(-7/3x)(-11/3).

  • 0
What are you looking for?