Login

How to factorise (a+b+c)2- (a-b-c)2 +4b2 - 4c2

(a + b + c)2  – (a – b – c) + 4b2 – 4c2

= (a + b + c + a – b – c) (a + b + c – a + b + c) + 4b2 – 4c2

= (2a) (2b + 2c) + 4b2 – 4c2

= 4a (b + c) + 4 (b + c) (b – c)

= 4 (b + c) (a + b – c)

  • 16
View Full Answer

expand it and the factorise

  • -13

(a+b+c)2-(a-b-c)2=4b2-4c2

=a2+ b2+ c2+ 2ab +2bc+ 2ac -a2 -b2- c2- 2ab -2bc+ 2ac +4b2 -4c2

=4ab +4ac +4b2 -4c2

=4 (ab +ac +b2 -c2)

4 (a (b+c)+ (b+c  )(b+c))

=4(b+c) (a+b-c)

  • 10
What are you looking for?