if 2 is the root of the equation x2+kx+12=0 and the equation x2+kx+q=0.has equal roots.find the value of q.

Given 2 is the root of x² + kx + 12 = 0 , hence substituting the value of x as 2 gives us zero

(2)² + 2k + 12 = 0

k = -16/2 = -8

Now given x² + kx + q has equal roots , so discriminant = 0 .... substituting k value in second equation

D = b² - 4ac = 0

(-8)² - 4(1)(q) = 0

4q = 64 , q = 64/4 = 16

Hence the value of q is 16