If 3x+[1/(2x)]=5, then the value of 8x3 +[1/(27x3 )] is - Maths - Polynomials

Question

If 3x+[1/(2x)]=5, then the value of 8x3
+[1/(27x3 )] is?

Anuradha Sharma · Accepted Answer

3x+12x=5 multiplying by 23 both side, we get 2x+13x=103taking cube we get, 8x2+127x3+3×2x×13x2x+13x=1000278x2+127x3+2103=1000278x2+127x3=100027-203=182027

If 3x+[1/(2x)]=5, then the value of 8x3 +[1/(27x3 )] is?

If 3x+[1/(2x)]=5, then the value of 8x³ +[1/(27x³)] is?