If O is the centre of a circle, ABCD is cyclic. Arc BCD subtends an angle of 140 degrees at  the centre , BC is produced to P and CD is joined. Find the measure of angle DCP.



BOD=140 degreeSO BRD=70 degreebecause angle made by an arc on center is double as that of made onthe circumfrence in the same segment.So now BRD=70 and BCDR is a cyclic quadrilateral so, BRD+BCD=18070+BCD=180BCD=110Now BCD and DCP are linear pair so, BCD+DCP=180DCP=70 degree

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from a point p two tangent pa and ab are drawn to a circle with centre o 
 
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Bhh
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