if sin (A+B) = cos ( A-B) = root3 / 2 and A, B (A B) are acute angles, find the values of

A and B .answeres pwweeesee !!! :)

sin(A+B) = cos(A-B)

sin(A+B) = sin(90-(A-B))

sin(A+B) = sin(90-A+B)

= A+B = 90-A+B

= 2A=90

=A=45

Now,

cos(A-B) = root3/2

cos(45-B) = cos30

=45-B = 30

=B = 45-30

= B = 15

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