if sin (A+B) = cos ( A-B) = root3 / 2 and A, B (A B) are acute angles, find the values of
A and B .answeres pwweeesee !!! :)sin(A+B) = cos(A-B)
sin(A+B) = sin(90-(A-B))
sin(A+B) = sin(90-A+B)
= A+B = 90-A+B
= 2A=90
=A=45
Now,
cos(A-B) = root3/2
cos(45-B) = cos30
=45-B = 30
=B = 45-30
= B = 15