If tanA=1/2 and tanB=1/3,Then Prove That: A+B=45Degree.
We know that Tan(A+B) = (TanA + TanB) / (1 - TanA.TanB)
= (1/2 + 1/3) / (1 - (1/2)(1/3) )
= (3+2 / 6) / ( 6-1 / 6)
= (5/6) / (5/6) = 1
As Tan 45o = 1 = Tan(A+B)
Hence A+B = 45o
If tanA=1/2 and tanB=1/3,Then Prove That: A+B=45Degree.
We know that Tan(A+B) = (TanA + TanB) / (1 - TanA.TanB)
= (1/2 + 1/3) / (1 - (1/2)(1/3) )
= (3+2 / 6) / ( 6-1 / 6)
= (5/6) / (5/6) = 1
As Tan 45o = 1 = Tan(A+B)
Hence A+B = 45o