If tanA=1/2 and tanB=1/3,Then Prove That: A+B=45Degree.

We know that Tan(A+B) = (TanA + TanB) / (1 - TanA.TanB)

                                           = (1/2  +  1/3) / (1 - (1/2)(1/3) )

                                           = (3+2 / 6)  / ( 6-1  / 6)

                                           = (5/6)  /  (5/6)    =   1

 

As Tan 45o = 1 = Tan(A+B)

Hence A+B = 45o

  • 2

We know that, Tan(A+B) = (TanA + TanB) / (1 - TanA.TanB)

Therefore,

tan(A + B) = { (1/2) + (1/3) } / { 1 - (1/2)(1/3) }                          {Replacing the values of tanA and tanB}

Rightarrow !, tan(A + B) = { ( 3+2 ) / ( 6 ) } / { ( 6-1 ) / (6) }

Rightarrow !, tan(A + B) = (5/6) / (5/6)

Rightarrow !, tan(A + B) = 1

Rightarrow !, tan(A + B) = tan (45°)                                                {since, tan 45° = 1}

Rightarrow !, A + B = 45°

Hence, proved!

 

  • 8
What are you looking for?