if x = 3+2 root 2 find find root x+1/root x

x = 3 + 2√2  

=> √x =  √(3+ 2√2)

=>  √[{(√2)2+ (√1)2 + (2)(√2)(√1)}]

=> √(√2+ √1)2        [a2+b2+2ab = (a+b)2]  

=> √2+ √1  

Putting the value of  √x in the given expression,  (√2+ √1)+1/(√2+ √1) =>  (√2+ 1+1)/( √2+ 1 )

=>  (√2+ 2)/ √2+ 1

rationalising the expression we get,  {(√2+ 2) (√2 -1)}/(√2+ 1)(√2- 1 )

=>  √2

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