if x = 3+2 root 2 find find root x+1/root x
x = 3 + 2√2
=> √x = √(3+ 2√2)
=> √[{(√2)2+ (√1)2 + (2)(√2)(√1)}]
=> √(√2+ √1)2 [a2+b2+2ab = (a+b)2]
=> √2+ √1
Putting the value of √x in the given expression, (√2+ √1)+1/(√2+ √1) => (√2+ 1+1)/( √2+ 1 )
=> (√2+ 2)/ √2+ 1
rationalising the expression we get, {(√2+ 2) (√2 -1)}/(√2+ 1)(√2- 1 )
=> √2