Login

In a frequency distribution, the mid-value of a class is 20 and the width of the class is 8.then what is the lower limit ?

Mid value (a) = 20

Width (h) = 8

Lower limit = a - h/2

= 20 - 8/2

= 20 - 4

= 16

Upper limit = a + h/2

= 20 + 8/2

= 20 + 4

= 24

Thus, the class limit = 16 - 24.

Also, a - h/2 and a + h/2 is the formula for finding out the lower and upper limit when class mark i.e mid value and class interval or width is given where a = mid value and h = width..

Hope u get it !!

:) :)

  • 63
View Full Answer
Mid value (a) = 20

Width (h) = 8

Lower limit = a - h/2

= 20 - 8/2

= 20 - 4

= 16

Upper limit = a + h/2

= 20 + 8/2

= 20 + 4

= 24

Thus, the class limit = 16 - 24.

Also, a - h/2 and a + h/2 is the formula for finding out the lower and upper limit when class mark i.e mid value and class interval or width is given where a = mid value and h = width.
  • 5
mid value = 20
width = 8
lower limit = 20 - 8 / 2
                 = 20 - 4
               = 16
upper limit = 20 + 8 / 2
                 = 20 + 4
                = 24
CLASS LIMIT = 16 - 24
  • 0
ans is lower limit 20
  • 0
no so sorry it is 16
  • -3
is a -h /2 a formula
  • -4
Please find this answer

  • 3
Please find this answer

  • 5
Mid value is 20 and width is 8.
The formula to find lower limit= a - h/2
                                              = 20-8/2
                                              =20-4
                                               =16
  • 7
Write the polynomial whose zeroes are-5 and 4
  • -4
The mean of 15 observation is 10 .If 2 is subtracted from each observation ,find the new mean
  • 0
Mid value (a) = 20

Width (h) = 8

Lower limit = a - h/2

= 20 - 8/2

= 20 - 4

= 16

Upper limit = a + h/2

= 20 + 8/2

= 20 + 4

= 24

Thus, the class limit = 16 - 24.

Also, a - h/2 and a + h/2 is the formula for finding out the lower and upper limit when class mark i.e mid value and class interval or width is given where a = mid value and h = width..

Hope u get it !!

:) :)
  • 0
Yy
  • 8
The lower limit is 16
  • 1
Punnu mere punnu
  • 0
Punnu
  • 2
Lower limit=a-h/2.If we consider a=20 and h=8,then 20-8/2=20-4=16.
  • 0
Ans.12
  • 0
yes you are correct
 
  • 0
Lower limit of the class is 16
  • 0
uyuuyuguuy

 
  • 0
16 is the lower limit
  • 0
Very bad
  • 0
Your answer....

  • 0
how many students are in the class
  • 0
Please find this answer

  • 0
Jai hind sathiyo
  • 0
Lower limit 20
  • 0
Devang ki Naukari Surendra Singh
  • 0
it is science in which deals with the collection, presentation, analysis and interpretation of the numerical data
  • 0
24 us lower limit and 16 is lower limit.
  • 0

Mid value (a) = 20

Width (h) = 8

Lower limit = a - h/2

= 20 - 8/2

= 20 - 4

= 16

Upper limit = a + h/2

= 20 + 8/2

= 20 + 4

= 24

Thus, the class limit = 16 - 24

  • 0
Let took it never is mind to
  • 0
What are you looking for?