in triangle ABC, if angleA+angle B=108 degree angle B+angle C=130 degree. Find angle A and angle B.

let Angle A = A , Angle B = B , Angle C = C

then,

A+B+C=180degree (equation 1)

A+B=108 degree (equation 2)

B+C=130degree(equation 3)

substitute B+C value in equation 1

so,

A + B + C = 180

A + 130 = 180

A = 180-130

A = 50 degrees

Now substitute value of A in equation 2 to find the vanue of B

A + B = 108 degrees

50+ B = 108

B = 108 - 50

B = 58 degrees

now substitute the value of B in equation 3 to find the value of C

B + C = 130 degrees

58 + C = 130

C = 130 - 58

C = 72 degrees

therefore Angle A = 50 degrees

Angle B = 58 degrees

Angle C = 72 degrees