Plzz answer it step by step plzzzz

x3-23x2+142x-120
x3-23x2+22x+120x-120
x3-x2-22x2+22x+120x-120
x2(x-1)-22x(x-1)+120(x-1)
(x2-22x+120)(x-1)
(x2-10x-12x+120)(x-1)
[x(x-10)-12(x-10)](x-1)
(x-12)(x-10)(x-1)

  • 7
First take out any one factor then keeping the value of that factor in polynomial solve it. After solve it by remainder theorem . Then go for divident=divisor X qoutient + remainder. After split middle term and u will have the factors which the answer of the qou.
  • 0
I have its solution image but its impossible to post
  • 0
What are you looking for?