Consider two ∆ABC and ∆PQR. In these two triangles B = Q = 90�, AB = PQ and AC = PR.We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQRWe need the help of SSS congruence rule.We have AB = PQ, and AC = PRSo, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QRNow, using Pythagoras theorems in ∆ABC and ∆PQRNow, in ∆ABC and ∆PQRAB = PQ, BC = QR, AC = PR∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule]So, we have AB = PQ, AC = PR, B = Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule.Hope! This will help you.Cheers!!!
