Rationalise the denominator of 2/√3 - √5

    23 - 5=-25 - 3=-25 - 3 × 5 + 35 + 3=-25 + 352 - 32=-25 + 35 - 3=-25 + 32=-5 + 3

  • 2
Akshat
  • -2
I Dont Know
  • -3
2/root3-root5*( multi)root3+root5/root3+root5


           2root3+2root5            

           3-5

2root3+2root5
         -2





HOPE IT HELPS



 
  • 0
2/√3-√5 * √3+√5/√3+√5
2*(√3+√5)/(√3-√5)(√3+√5)
2√3+2√5/(√3)2-(√52)
2√3+2√5/-2
-2√3+2√5/2
-√3-√5
  • 1
Answer will be 2 root3 +2root5 / 2
  • 0
-root5-root3
  • 0
What are you looking for?