solve : a (3+4i) ^ -1 b (2+3i) ^ 2 x (3+2i) ^ -1 - Maths - Complex Numbers and Quadratic Equations

Question

solve :
a (3+4i) ^ -1
b (2+3i) ^ 2 x (3+2i) ^ -1

brainmasswriter2 · Accepted Answer

1)

${(3 + 4 i)}^{- 1} = \frac{1}{(3 + 4 i)} \times \frac{(3 - 4 i)}{(3 - 4 i)} = \frac{3 - 4 i}{(9 + 16)} = \frac{3}{25} - \frac{4 i}{25}$ .

2)

$({2 + 3 i)}^{2} ({3 + 2 i)}^{- 1} = \frac{({2 + 3 i)}^{2}}{(3 + 2 i)} \times \frac{3 - 2 i}{3 - 2 i} = \frac{9 + 46 i}{13}$

solve : a. (3+4i) ^ -1 b. (2+3i) ^ 2 x (3+2i) ^ -1