solve the quadratic equation : 9x+2--6X3x+1+1=0 Share with your friends Share 0 Varun.Rawat answered this 9x+2 - 6.3x+1 + 1 = 0⇒32x+2 - 3 . 2 . 3x+1 + 1 = 0⇒3x+2 . 3x+2 - 2 . 3x+2 + 1 = 0 ⇒y2 - 2y + 1 = 0 put 3x+2 = y⇒y2 - y - y + 1 = 0⇒yy - 1 - 1y - 1 = 0⇒y - 1y - 1 = 0⇒y - 1 = 0 or y - 1 = 0⇒y = 1 or y = 1Now, 3x+2 = 1⇒3x+2 = 30⇒x + 2 = 0⇒x = -2 1 View Full Answer