sum of coefiicients in expansion of (1+x)^n Share with your friends Share 0 Varun.Rawat answered this We know that,1+xn = C0n + C1nx + C2nx2 + ......+Cn-1n . xn-1 + Cnn xnput x = 1 in the above expansion, we get1+1n = C0n + C1n + C2n + ........+Cn-1n + Cnn⇒C0n + C1n + C2n + ........+Cn-1n + Cnn = 2n⇒sum of the coefficients in the expansion of 1+xn = 2n 0 View Full Answer