let the fixed charge = Rs x and
the charges per km =Rs y
acc. to question,
x + 10y = 105............(1)
x + 15y = 155..............(2)
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-5y = -50
y = 10
put in (1) , we get
x + 10 (10) = 105
x + 100 = 105
x = 105 - 100
x = 5
thus, the fixed charge = x = Rs. 5 and
the charge per km = Rs. y = Rs. 10