the rating of an electric heater is 1100W ,220V calculate resistance when it operates at 220V also calculate - Physics - Electricity

Question

the rating of an electric heater is 1100W ,220V calculate
resistance when it operates at 220V also calculate the energy
consumed in KWH in the month of november of the heater, if used
daily for four hours at the rated voltage

brainmasswriter1 · Accepted Answer

$P = \frac{V^{2}}{R} \Rightarrow R = \frac{V^{2}}{P} = \frac{{(220)}^{2}}{1100} = 44 Ω$

So resistance when it operates at 220 V is 44 ohm.

$P o w e r = \frac{E n e r g y}{t i m e} \Rightarrow E n e r e g y (E) = P o w e r (P) \times T i m e (t)$

In a day it is operated for four hours and in a month of November there are 30 days. So total number of hours for which it is operated in a month of November=(30)(4)=120 hours

So t=120 hours

and P=1100W

So we get:

$E = 1100 \times 120 = 132000 = 132 K W H$

the rating of an electric heater is 1100W ,220V .calculate resistance when it operates at 220V. also calculate the energy consumed in KWH in the month of november of the heater, if used daily for four hours at the rated voltage