This question is from RD Sharma page 2.34 exercise2.1,Q10

rnQ If alpha and Beeta are the zeroesof the quadratic polynomial3s square- 6s+4find

rnalpha beeta

rn+beeta alpha

rn+2(1 alpha+1 beeta)

rn= 3 alpha beeta

rnPlease don 't mind the way I have written the question actually when I wrote it in one go it said that my input is very large.

rnrn

#### Answers

This question is out of syllabus of class 10th as it has imaginary roots

exactly what we have to find in this ?

yes nitin is right

hey did is a very easy one

u will get first alpha square and beeta square by alpha and beetha

plus u take the lcm and add 3 alpha

and just substitute the values and use the formula

then get the answer

Thanks for telling me...I am glad its not in the syllabus.

Its good that you have done it but the above answerers say that it is out of syllabus.