Three identical capacitors C _{ 1 } , C _{ 2 } and C _{ 3 } of capacitance 6 μ F each are connected to a 12 V battery as shown.

Find

(i) charge on each capacitor

(ii) equivalent capacitance of the network

(iii) energy stored in the network of capacitors

Ajay T.s. , Meritnation Expert added an answer, on 31/12/10

Hi Sanal!

The solution to the problems is as follows:

** (i) ** **Charge on each capacitors: **

The capacitors C_{1} and C_{2} are in series. Therefore the equivalent capacitance of this combination is

As you know, charge Q= CV.

Therefore charge on C_{1}= charge on C2=3µF×12V=36µC.

Charge on C_{3}=6µF×12V=72µC.

** (ii) ** **Equivalent capacitance of the network: **

The equivalent capacitance of the series combination of C_{1} and C_{2} is 3µF. This is in parallel with C_{3.} Therefore, the equivalent capacitance of the network C_{eq}=3µF+ 6µF =9µF.

** (iii) ** **Energy stored in the network of capacitors: **

Cheers!!

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