011-40705070  or  
Call me
Download our Mobile App
Select Board & Class
  • Select Board
  • Select Class

 Three identical capacitors C 1 , C 2  and C 3  of capacitance 6  μ F each are connected to a 12 V battery as shown.


(i) charge on each capacitor

(ii) equivalent capacitance of the network

(iii) energy stored in the network of capacitors

Asked by Rahul Pillai (student) , on 31/12/10

Become Expert
Score more in Physics
Start Now with Video Lessons, Sample Papers, Revision Notes & more for Class-XII-Science - CBSE 


Hi Sanal!

The solution to the problems is as follows:

(i)  Charge on each capacitors:

The capacitors C1 and C2 are in series. Therefore the equivalent capacitance of this combination is

As you know, charge Q= CV.

Therefore charge on C1= charge on C2=3µF×12V=36µC.

Charge on C3=6µF×12V=72µC.

(ii)  Equivalent capacitance of the network:

The equivalent capacitance of the series combination of C1 and C2 is 3µF. This is in parallel with C3. Therefore, the equivalent capacitance of the network Ceq=3µF+ 6µF =9µF.

(iii)  Energy stored in the network of capacitors:


Posted by Ajay (MeritNation Expert) on 31/12/10

This conversation is already closed by Expert

Ask a QuestionHave a doubt? Ask our expert and get quick answers.
Show me more questions