Two chords AB and CD of length 5cm and 11cm respectively of a circle are parallel to each other on opposite sides of its centre.If the distance between AB nad CD is 6cm. Find the radius...
Draw OM ⊥ AB and ON ⊥ CD. Join OB and OD.
(Perpendicular from the centre bisects the chord)
Let ON be x. Therefore, OM will be 6− x.
In ΔMOB,
In ΔNOD,
We have OB = OD (Radii of the same circle)
Therefore, from equation (1) and (2),
From equation (2),
Therefore, the radius of the circle iscm.
cheers.. thumbz up