Two chords AB and CD of length 5cm and 11cm respectively of a circle are parallel to each other on opposite sides of its centre.If the distance between AB nad CD is 6cm. Find the radius...

Draw OM ⊥ AB and ON ⊥ CD. Join OB and OD.

(Perpendicular from the centre bisects the chord)

Let ON be x. Therefore, OM will be 6− x.

In ΔMOB,

In ΔNOD,

We have OB = OD (Radii of the same circle)

Therefore, from equation (1) and (2),

From equation (2),

Therefore, the radius of the circle iscm.


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