ntainer at the rate of 192.5 litres per minute.Find the rate of flow of water in the pipe in km/h.use pi=22/7
--The collecting rate in the container ( increasing) = - the follow rate in the pipe (decreasing).
Thus the rate of flow of water in the pipe = - 192.5 liters / minute.
To change the units, recall that 1 liter = 1× 10^(-3) m^3 = (1 × 10^(-3))×10^(-9) = 1 × 10^(-12) km^3.
and 1 minute = 1/60 hour. So
the rate of flow of water in the pipe = - 192.5 × (1 × 10^(-3))×10^(-9) × 1/60 km^3 / h
--You will need the density of water.
Consider the water flown in one minute.
volume = 192.5 L = 192.5 cm³
When you divide this volume by the area of cross section of the pipe,you will get the length of water flow seen in one minute(simply the speed)
v = 192.5 cm³ / (22/7)49cm²
= 1.25 cm per minute
= 1.25 x 10^(-24) x 60 km per hour
--r = d/2 =7/2 =3.5
Volume =pi*r^2.(flow of water in litre/min) =192.5
=(22/7)(3.5)^2*(x say) =192.5
x =(192.5)(7/22)(1/3.5)^2 =5/minutes
=5000 cm/minutes
=5000/100 meters/minutes
= 50 meters/minutes
= 50/1000 km/minutes
= 50*60/1000 km/hr
=3000/1000km/hr
= 3km/hr ...............Ans
