What is the least number which when diminished by 5, is divisible by each one of 21, 28, 36, 45?

a) 425

b) 1259

c)1260

d)1265

The prime factorisation of 21, 28, 36 and 45 is,21 = 3 × 728 = 2 × 2 × 736 = 2×2×3×345 = 3×3×5LCM of 21, 28, 36 and 45 = 2×2×3×3×5×7 = 1260Now, the required number = 1260 + 3 = 1263

 

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