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 what is the oxidation no of S in SO2  ?

Dear Student,

@Sarsiz, You provided correct reply. I just want to add a few more points.

Structure of SO2 is O=S=O which is bent. Sulphur is less electronegative than oxygen, so oxygen gets -1 charge and S gets +1 charge on each single bond. therefore, sulphur has total 4+ charge resulting its oxidation number +4 and  -2 oxidation number for each oxygen atom.

 

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Its so simple.+4. Its an oral question.

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well i got confused bcoz of sumthing...........

S being +4 was getting oxidised as well as O which changed frm 0 to -2.

tht ain't possible u know !!

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 the Q is

FeS2 + O2 ---> Fe2O3 + SO2...........

can u tell the OHR and RHR in this ??

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Please don't right in short forms. I am not familiar with such words.

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What is OHR and RHR? I am not familiar with such short forms.

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 OHR is oxidation half reaction while RHR is reduction half reaction............

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STEP (1)..first observe the reaction and find which compound ius getting oxidized and which one is reducing

HERE REACTION = FeS2+O2 ------ Fe2O3 +SO2

SO HERE REACTIONS ARE ..(half reaction ) 


are Fes2-----1/2Fe2o3 ...( 1/2Fe2O3 ,, because .. balancing that reaction..)..BALANCING FE ATOM..

so oxidation number changes from..+2 to +3

and Fes2-------2SO2..OXIDATION NUMBER OF CHANGES FROM ..-1 TO +4


... NOW EQUATE THE OXIDATION NUMBER AND ADD THE EQUATIONS ..

THEN  ADD H2O TO BALANCE NO OF O AND H ATOM

AND SOLVE...

Sarsiz Chauhan

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STEP (1)..first observe the reaction and find which compound ius getting oxidized and which one is reducing

HERE REACTION = FeS2+O2 ------ Fe2O3 +SO2

SO HERE REACTIONS ARE ..(half reaction )

are Fes2-----1/2Fe2o3 ...( 1/2Fe2O3 ,, because .. balancing that reaction..)..BALANCING FE ATOM..

so oxidation number changes from..+2 to +3

and Fes2-------2SO2..OXIDATION NUMBER OF CHANGES FROM ..-1 TO +4

... NOW EQUATE THE OXIDATION NUMBER AND ADD THE EQUATIONS ..

THEN  ADD H2O TO BALANCE NO OF O AND H ATOM

AND SOLVE...

Sarsiz Chauhan

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Do u know I am in 10th standard and I am solving querries of 11th standard

I think u don't know that this qestion is of IIT level. This type of question often come in different ways.

Have a happy day.

Sarsiz.

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If  u have more querries I am here to solve for you

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 well if u observe carefully both the "half reactions" that u have written are undergoing OXIDATION......... this can't be possible so m sorry to say tht ur ans iis wrong :(

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Thank you for telling my mistake. I didn't paid much attention to my solution. So I am really very sorry. But no problem I have solved it  and I think it should work.

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We begin by balancing Fe
2FeS2 + O2 → Fe2O3 + SO2
and then S
2FeS2 + O2 → Fe2O3 + 4SO2
Finally, we balance O by adjusting the coefficient for O2
2FeS2 + 112O2 → Fe2O3 + 4SO2
4FeS2 + 11O2 → 2Fe2O3 + 8SO2
Sarsiz Chauhan
 

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I also have a different method to solve this question. Plz let me know if u want to see that method.

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In second last step its 11/2 O2

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 yes i would like to know that methhod

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