Write each of the following in the simplest form:
cot-1 { a/root(x2​ - a2)}, |x| > a
 

Dear student,

Let y = cot-1ax2-a2, x>aputting a = xcosθ such that θ= cos-1xa y = cot-1xcosθx2-x2cos2θ=  cot-1xcosθxsinθ= cot-1cotθ= θ=cos-1xaSo  cot-1ax2-a2=cos-1xa
Regards

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