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Aatmeeya Shetty
Subject: Physics
, asked 4 hours, 41 minutes ago
Pls solve asap plsss
Answer
2
Aatmeeya Shetty
Subject: Physics
, asked 4 hours, 59 minutes ago
Solve q18 asap
Answer
1
Aatmeeya Shetty
Subject: Physics
, asked 7 hours, 53 minutes ago
Pls solve it asap
Answer
1
Riddhi Khera
Subject: Physics
, asked 8 hours, 39 minutes ago
Vernier Calipera and screw gauge explanation pls
Answer
1
Aatmeeya Shetty
Subject: Physics
, asked 10 hours, 42 minutes ago
Solve it asap
Answer
3
Rama Mittal
Subject: Physics
, asked 10 hours, 45 minutes ago
In dimensional analysis formula how to take the value of a, b and c ?????? Plz explain
Answer
1
Maanya
Subject: Physics
, asked 12 hours, 28 minutes ago
y=sinx+cosx. find the maximum and minimum value of y and draw the graph.0 is less than or equal to x and x is less than or equal to 2pie.
Answer
1
Aatmeeya Shetty
Subject: Physics
, asked 19 hours, 24 minutes ago
Pls solve it asap
Answer
1
Aatmeeya Shetty
Subject: Physics
, asked 1 day, 3 hours ago
Solve it asap
Answer
1
Aatmeeya Shetty
Subject: Physics
, asked 1 day, 4 hours ago
Pls solve on a sheet of paper
Answer
1
Harshita Roy
Subject: Physics
, asked 1 day, 7 hours ago
A charge Q is divided into 2 parts such that they experience maximum electrostatic repulsion when placed at a certain distance apart. Find the division.
Answer
1
Kaushiki Dwivedi
Subject: Physics
, asked 1 day, 8 hours ago
Expert please answer both the questions fast
Answer
1
Sugourna Paul
Subject: Physics
, asked 1 day, 12 hours ago
A particle starts moving along x-axis
from t = 0, its position varying with time
as x=2t^3-3t^2+1.
(a) At which time instants is its velocity
zero?
(b) What is the velocity when it passes
through origin?
Answer
1
Sugourna Paul
Subject: Physics
, asked 1 day, 12 hours ago
The acceleration of a particle is given by a=t^3+t^2+5, where a is in ms^-2 and t in sec. At t=1s, the displacement and velocity are 8.30m and 6.25m/s, respectively. Calculate the displacement and velocity at t=2s.
Answer
1
Sugourna Paul
Subject: Physics
, asked 1 day, 12 hours ago
The velocity of a particle is given by v=12+3(1+7t^2).What is the
acceleration of the particle?
Answer
1
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What are you looking for?

from t = 0, its position varying with time

as x=2t^3-3t^2+1.

(a) At which time instants is its velocity

zero?

(b) What is the velocity when it passes

through origin?

acceleration of the particle?