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Megha
Subject: Physics
, asked on 24/5/18
Can a vector have zero component along a line and still have a non zero magnitude?
Answer
2
Kumar Rajesh
Subject: Physics
, asked on 23/5/18
The edges of a parallelepiped are given by the vector (2i+3j+4k) and 5j+mk. What should be the value of m in order that the volume of the parallelepiped be 24?
Answer
1
Ghosh Brothers
Subject: Physics
, asked on 23/5/18
A bomb at rest is exploded and the pieces are scattered in all directions with the maximum velocity of 20 m per second. Dangerous distance from the spot is ?
Answer
1
Kumar Rajesh
Subject: Physics
, asked on 22/5/18
For what value of m a vector=2i+3j-6k is perpendicular to b vector 3i-mj+6k.
Answer
3
Aditya Anand
Subject: Physics
, asked on 22/5/18
Please answer Q.22
22.
A particle is moving on a circular path of radius uniform velocity v. The change in velocity when the particle moves from P to Q is
$\left(\angle POQ=40\xb0\right)$
$\left(A\right)2v\mathrm{cos}40\xb0\left(B\right)2v\mathrm{sin}40\xb0\phantom{\rule{0ex}{0ex}}\left(C\right)2v\mathrm{sin}20\xb0\left(D\right)2vcos20\xb0\phantom{\rule{0ex}{0ex}}$
Answer
1
Aditya Anand
Subject: Physics
, asked on 22/5/18
Please answer Q.20:
20. Figure below shows a body of mass M moving with the uniform speed on a circular path of radius, R. What is the change in acceleration in going from P
_{1}
to P
_{2}
$\left(\mathrm{A}\right)\mathrm{Zero}\left(\mathrm{B}\right){\mathrm{V}}^{2}/2\mathrm{R}\phantom{\rule{0ex}{0ex}}\left(\mathrm{C}\right)2{\mathrm{V}}^{2}/2\mathrm{R}\left(\mathrm{D}\right)\frac{{\mathrm{V}}^{2}}{\mathrm{R}}\times \sqrt{2}$
Answer
1
Kumar Rajesh
Subject: Physics
, asked on 22/5/18
an object of mass m is covering distance x,is proportional to t^3/2 , where t is the time elapsed .
(a) what conclusion might you draw about the acceleration? Is it increasing,decreasing ,zero or constant
(b) what will be the force acting on the object?
Answer
1
Ghosh Brothers
Subject: Physics
, asked on 21/5/18
a person walking in rain feels the velocity o the rain as twice to his velocity. At which anglehe should hold the umbrella with vertical if he moves forward , if it id raining vertically downwards
Answer
1
Himanshu Sharma
Subject: Physics
, asked on 21/5/18
What is the formula to find magnitude and direction in resolution of vectors?
Answer
1
Devesh Lal
Subject: Physics
, asked on 17/5/18
This is urgent
Answer
1
Om
Subject: Physics
, asked on 16/5/18
Can someone answer these
Answer
1
Romil Singh
Subject: Physics
, asked on 13/5/18
The magnitudes of vectors
$\overrightarrow{OA},\overrightarrow{OB}\mathrm{and}\overrightarrow{OC}$
in figure (2-W3) are equal. Find the direction of
$\overrightarrow{OA}+\overrightarrow{OB}-\overrightarrow{OC}$
.
Answer
4
Tanya Shankar
Subject: Physics
, asked on 11/5/18
Please explain a vector can be shifted without changing its values its length and direction and not changed and displacement vectors represent only the overall effect of the motion but not the motion itself.
Answer
2
Romil Singh
Subject: Physics
, asked on 8/5/18
Q. Find the derivative
(vi) y =
$\frac{2x+3}{4x+5}$
Answer
1
Priyanshi
Subject: Physics
, asked on 8/5/18
Solve the qus:
295. A boy begins to walk eastward along a street infront of his house and the graph of his displacement from house is shown in the following figure. His average speed for the whole time interval is equal to:
(a) 8 m/min (b) 6 m/min
(c) 8/3 m/min (d) 2 m/min
Answer
1
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22.A particle is moving on a circular path of radius uniform velocity v. The change in velocity when the particle moves from P to Q is $\left(\angle POQ=40\xb0\right)$$\left(A\right)2v\mathrm{cos}40\xb0\left(B\right)2v\mathrm{sin}40\xb0\phantom{\rule{0ex}{0ex}}\left(C\right)2v\mathrm{sin}20\xb0\left(D\right)2vcos20\xb0\phantom{\rule{0ex}{0ex}}$

20. Figure below shows a body of mass M moving with the uniform speed on a circular path of radius, R. What is the change in acceleration in going from P

_{1}to P_{2}$\left(\mathrm{A}\right)\mathrm{Zero}\left(\mathrm{B}\right){\mathrm{V}}^{2}/2\mathrm{R}\phantom{\rule{0ex}{0ex}}\left(\mathrm{C}\right)2{\mathrm{V}}^{2}/2\mathrm{R}\left(\mathrm{D}\right)\frac{{\mathrm{V}}^{2}}{\mathrm{R}}\times \sqrt{2}$

(a) what conclusion might you draw about the acceleration? Is it increasing,decreasing ,zero or constant

(b) what will be the force acting on the object?

(vi) y = $\frac{2x+3}{4x+5}$

295. A boy begins to walk eastward along a street infront of his house and the graph of his displacement from house is shown in the following figure. His average speed for the whole time interval is equal to:

(a) 8 m/min (b) 6 m/min

(c) 8/3 m/min (d) 2 m/min