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Saanvi Chauhan
Subject: Vedic Math
, asked on 21/8/16
DEFINE-
1- PYTHAGOREAN THEOREM
2- PYTHAGOREAN TRIPLETS
3- HYPOTENUSE
Answer
1
Theodore Delacroix
Subject: Vedic Math
, asked on 25/5/16
in vedic maths, till which no do we consider it close to the base.
[or which percent out of the base[ which is expressed as 1 followed by certain zeros]
Answer
1
Aditya
Subject: Vedic Math
, asked on 7/5/16
solve
Answer
1
Aditya
Subject: Vedic Math
, asked on 7/5/16
solve
Answer
6
Ejaz
Subject: Vedic Math
, asked on 11/2/16
what must we take base for 50
2
?
Answer
2
Harsh
Subject: Vedic Math
, asked on 29/8/16
find the base of a triangle whose altitude is 10cm and area is 0.5m2
Answer
2
Mahi Jaiswal
Subject: Vedic Math
, asked on 21/8/16
square of 23 using vedic maths
Answer
2
Harshita Mishra
Subject: Vedic Math
, asked on 15/8/16
by splitting into prime factors , find the square root of : 194481
Answer
1
Nirbhay Quantum
Subject: Vedic Math
, asked on 15/8/16
Let x
1
, x
2
, x
3
be the roots of the equation x
3
+ 3x + 5 = 0 . What is the value of the expression =>>>
(x
1
+ ( 1 / x
1
)) + ( x
2
+ (1/x
2
) ) + (x
3
+ (1/x
3
))
Answer
1
Vikash (tutor)
Subject: Vedic Math
, asked on 3/8/16
Write a pythagorean triplet whose smallest no. is 6 ( PLS DEAR EXPERTS ANS URGENTLY)
Answer
1
Ritika Srivastava
Subject: Vedic Math
, asked on 1/8/16
squares and cubes till 20
Answer
3
Manbir Singh Nagi
Subject: Vedic Math
, asked on 3/7/16
what is the root of 256
Answer
3
Anshul Sharma
Subject: Maths
, asked on 20/4/16
squares of no s like 97 by using vedic math
Answer
1
Aishwarya Jee
Subject: Vedic Math
, asked on 8/4/16
Let x,y,z be non-zero real numbers such that x/y+y/z+z/x=7 and y/x+z/y+x/z=9,then x^3/y^3+y^3/z^3+z^3/x^3 -3 is equal to: A. 152 b.153 c. 154 d. 155
Answer
1
Vishesh Jindal
Subject: Vedic Math
, asked on 20/3/16
Find cube rootof 5832
Answer
1
1
2
3
4
5
Next
What are you looking for?
1- PYTHAGOREAN THEOREM
2- PYTHAGOREAN TRIPLETS
3- HYPOTENUSE
[or which percent out of the base[ which is expressed as 1 followed by certain zeros]
(x1 + ( 1 / x1 )) + ( x2 + (1/x2 ) ) + (x3 + (1/x3 ))