1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

what is hit and trial method .

If the mean of the number 7,3,8,4,x,7,9,7 and 12 is 7, then the difference between the median and mode of the numbers 12,10,8,10,x,7,6,8 and 6 is:

(a)0. (b)1. (c)2. (d)3

If the median of the distribution is given below is 28.5, find the values of x and y.

Class interval

0 − 10

5

10 − 20

x

20 − 30

20

30 − 40

15

40 − 50

y

50 − 60

Total

60

The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

10. If median = 15 and mean = 16, find mode of the distribution

The median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

how to calculate mode if two classes have same and highest frequency (bimodal) ?

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.

how to find xi?

The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.

What is the formula to use median when more than ogive is given?

One word answer-VERY URGENT***

1) Difference between any 2 consecutive class marks (9 letters)

2)Graphical Representation (in rectangles) between class marks and respective frequencies (16 letters)

3)Graphical Representation (in rectangles) between class intervals and respective frequencies ( 9 letters)

4)Data in tabular form (7 letters)

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days

0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students

11

10

4

3

1

In the step deviation method,

What is the meaning of u_{i }?

1.Find the missing frequency f, if the mode of the given data is 154.

Classes

120-130

130-140

140-150

150-160

160-170

170-180

Frequency

2

8

12

f

9

7

plzz give an answer fast....

IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.

what is hit and trial method .

If the mean of the number 7,3,8,4,x,7,9,7 and 12 is 7, then the difference between the median and mode of the numbers 12,10,8,10,x,7,6,8 and 6 is:

(a)0. (b)1. (c)2. (d)3

If the median of the distribution is given below is 28.5, find the values of

xandy.Class intervalFrequency0 − 10

5

10 − 20

x20 − 30

20

30 − 40

15

40 − 50

y50 − 60

5

Total

60

The median from the table is

value 7, 8, 9, 10, 11, 12 ,13

frequency 2, 1, 4, 5, 6, 1, 3

if the median of the following frequency distribution is 24. find the missing frequency x :

Age Number of persons

0 - 10 5

10 - 20 25

20 - 30 x

30 - 40 18

40 - 50 7

find the missing frequencies if N=100 and median is 32.

marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total

no. of students-10 ,? ,25 ,30 ,? ,10 ,100.

10. If median = 15 and mean = 16, find mode of the distributionThe median of the following distribution is 30. Find the missing frequencies f1 and f2:

Class frequency

0-10 10

10-20 10

20-30 f1

30-40 30

40-50 f2

50-60 10

Total 100

age (in years):

0-1 1-2 2-3 3-4 4-5 5-6 6-7

no. of pumps:

12 18 45 23 12 08 04

the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?

how do we find mean using step deviation method if the classes are unequal?

should we make the classes equal in such a case?

how to find the mean if the class intervals are unequal??

like fr e- 0-10,10-30,30-35....

how to calculate mode if two classes have same and highest frequency (bimodal) ?

The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______

the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.

how to find xi?

The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.

classes frequency

0-100 8

100- 200 12

200-300 x

300-400 20

400-500 14

500-600 7

What is the formula to use median when more than ogive is given?

One word answer-

VERY URGENT***1) Difference between any 2 consecutive class marks (9 letters)

2)Graphical Representation (in rectangles) between class

marksand respective frequencies (16 letters)3)Graphical Representation (in rectangles) between class

intervalsand respective frequencies ( 9 letters)4)Data in tabular form (7 letters)

median.

Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90

frequency 10 8 12 24 6 25 15

A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Number of days0 − 6

6 − 10

10 − 14

14 − 20

20 − 28

28 − 38

38 − 40

Number of students11

10

7

4

4

3

1

Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100

No. of students 5 9 17 29 45 60 70 78 83 85

In the step deviation method,

What is the meaning of

u_{i }?