0 3 g of an oxalate salt was dissolved in 100 ml solution The solution required 90 mL of - Chemistry - Some Basic Concepts of Chemistry

Question

0 3 g of an oxalate salt was dissolved in 100 ml solution The
solution required 90 mL of N/20 KMnO4 for complete oxidation The %
of oxalate ion in salt is:

A 33 % B 66 % C 70% D 40%

Geetha · Accepted Answer

Redox changes areMn7++5e-→Mn++C22-→2 C4+ + 2e-Milliequivalent of oxalate ion = Milliequivalent of KMnO4wE × 1000 - 90 × 120EC2O42- = 882 = 44wE  × 1000 = 9020w =9020 × 441000  = 0
198Since 0
3 g of oxalate sample has = 0
198 g oxalate ion% of oxalate in  sample = 0
198 × 1000 3 = 66 %
Thus option B is correct

0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 mL of N/20 KMnO4 for complete oxidation. The % of oxalate ion in salt is: A. 33 % B. 66 % C. 70% D. 40%

0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 mL of N/20 KMnO4 for complete oxidation. The % of oxalate ion in salt is:

A. 33 % B. 66 % C. 70% D. 40%