0.59 g of silver salt of an organic acid on ignition gave 0.36 g of pure silver. What is the basic its of the acid ?
Your query is incomplete. You have not given the molar mass of acid. I have checked this question. The correct question is :
0.59 g of silver salt of an organic acid( M = 210g) on ignition gave 0.36 g of pure silver. What is the basic its of the acid?
Molar mass of Ag = 107.87 g mol-1
Mass of acid taken = 0.59 g
Molar mass of acid = 210 g mol-1
Number of moles of Ag = 0.36 / 107.87
= 3.34
10-3
Mass of acid formed = 0.59 - 0.36
= 0.23 g
Number of moles of acid = 0.23 / 210
= 1.09
10-3 moles
Now 1.0910-3 mole of acid is formed and 3.3410-3 moles of silver are released. It means 3 atoms of silver are in the reactant with the acid according to the law of conservation of mass. The reaction will be as follows:
Ag3R → H3R + 3Ag
It means the basicity of acid is 3 as silver will replace the hydrogen of acid.
0.59 g of silver salt of an organic acid( M = 210g) on ignition gave 0.36 g of pure silver. What is the basic its of the acid?
Molar mass of Ag = 107.87 g mol-1
Mass of acid taken = 0.59 g
Molar mass of acid = 210 g mol-1
Number of moles of Ag = 0.36 / 107.87
= 3.34
Mass of acid formed = 0.59 - 0.36
= 0.23 g
Number of moles of acid = 0.23 / 210
= 1.09
Now 1.09
Ag3R → H3R + 3Ag
It means the basicity of acid is 3 as silver will replace the hydrogen of acid.