1 Find energy expression of n=1 to n=7 for z=12 Find energy of photon required to jump n=1 - Science - Structure of the Atom

Question

1   F i n d   e n e r g y   e x p r e s s i o n
  o f   n = 1   t o   n = 7   f o r  
z = 1 2   F i n d   e n e r g y   o f   p h o t
o n   r e q u i r e d   t o   j u m p n = 1   t
o   n = 2 n = 2   t o   n = 3 n = 3   t o
  n = 4 n = 4   t o   n = 5 n = 5   t o  
n = 6 n = 6   t o   n = 7 n = 7   t o   n = 8

Sakshi Kanwar · Accepted Answer

Daer Student

1 The expression isE=-13
6[1nf2-1ni2]eV2) from n=1 to n=2E=-13 6[14-1]=3
4*3=10
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1 . F i n d e n e r g y e x p r e s s i o n o f n = 1 t o n = 7 f o r z = 1 2 . F i n d e n e r g y o f p h o t o n r e q u i r e d t o j u m p . n = 1 t o n = 2 n = 2 t o n = 3 n = 3 t o n = 4 n = 4 t o n = 5 n = 5 t o n = 6 n = 6 t o n = 7 n = 7 t o n = 8

$1 . F i n d e n e r g y e x p r e s s i o n o f n = 1 t o n = 7 f o r z = 1 2 . F i n d e n e r g y o f p h o t o n r e q u i r e d t o j u m p . n = 1 t o n = 2 n = 2 t o n = 3 n = 3 t o n = 4 n = 4 t o n = 5 n = 5 t o n = 6 n = 6 t o n = 7 n = 7 t o n = 8$