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1. From a rope 15 m long, 4 1 3 m is cut off and  3 5 of the remaining is cut off again. Find the length of the remaining part of the rope.

2. Perimeter of a rectangle is 2 m less than  2 5 of the perimeter of the square. If the perimeter of the square is 40 m, find the length and breadth of the rectangle given that the breadth is  1 3 of the breadth.

Dear student
Que 2Given:Perimetr of square =40mNow, A.T.QPerimter of rectangle=25Perimeter of square-2⇒Perimter of rectangle=2540-2    Given⇒Perimter of rectangle=16-2⇒Perimter of rectangle=14mAlso, given Breadth b=13length l⇒b=13l  So, perimeter of rectangle=2l+b⇒14=21+13l⇒7=43l⇒l=214mand Breadthb=13×214=74m 
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Hello Vanshika, from 15 m part 4 1/3 ie. 13/3 has been cut off
So balance = 15 - 13/3 = 32/3 m 
Now 3/5 of this is cut off. So 2/5 of this remains
Hence remaining part 2/5 * 32/3 = 64/15 m or 4 + 4/15 m
So 

 
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Hello Vanshika, perimeter of square is 40 m
2/5 of this 2/5 * 40 = 16 m
By the problem perimeter of rectangle = 16 - 2 = 14 m
Given length is 3 b So perimeter = 8 b
By the problem 8 b = 14 
Or b = 7/4 m
Hence length = 21/4 m and breadth = 7/4 m
 
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