1 . lim x → 0 sin ( π cos 2 ( tan ( sin x ) ) ) x 2 i s e q u a l t o : ( a ) π ( b ) π 4 ( c ) π 2 ( d ) None of these Share with your friends Share 0 Aarushi Mishra answered this limx→0sinπ cos2tan sin xx2We know sin θ=sin π-θlimx→0sinπ cos2tan sin xx2=limx→0sinπ-π cos2tan sin xx2=limx→0sinπ1-cos2tan sin xx2Use 1-cos2θ=sin2θ=limx→0sinπsin2tan sin xx2=limx→0sinπ sin2tan sin xx2×π sin2tan sin xπ sin2tan sin x=limx→0sinπ sin2tan sin xπ sin2tan sin x×π sin2tan sin xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×limx→0π sin2tan sin xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0sin2tan sin xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sin2tan sin xx2×tan2 sin x×tan2 sin x=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sin2tan sin xtan2 sin x×tan2 sin xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sin2tan sin xtan2 sin x×limx→0 tan2 sin xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sintan sin xtan sin x2×limx→0 tan2 sin xx2×sin2x×sin2x=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sintan sin xtan sin x2×limx→0 tan2 sin xsin2x×limx→0sin2xx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sintan sin xtan sin x2×limx→0 tan sin xsin x2×limx→0sinxx2=limx→0sinπ sin2tan sin xπ sin2tan sin x×π ×limx→0 sintan sin xtan sin x2× limx→0tan sin xsin x2×limx→0sinxx2Use limθ→0sinθθ=1 and limθ→0tanθθ=1=1×π ×1× 1×1=π 0 View Full Answer