1.Sam has 7 chocolates more than two times the chocolates Ben has. If Sam has 47 chocolates ,how many chocolates does Ben have ?
2.Find the diagonal of a rectangle whose length is 12cm and width is 9cm .
3.Simplify:[−845÷249]–[−45]

Dear Student,

1.Let the number of chocolates Ben has be x and number of chocolates Sam has be 2x+7Then according to the question,2x+7=472x=40x=20Ben has 20 chocolates2.Using Pythagoras Theorem,(Diagonal)2=122+92=225 Length of diagonal=15 cm3. -845249-(-45)=-3.39+45=41.61


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