1. the sum of the ages of a man and his son is 45 years.5 years ago,the product of their ages was 4 times the man's age at that time.

2.7 yrs ago varun's age was 5 times the square of swati's age.3 yrs hence her age will be two fifth of varun's age.find der ages

3.the speed of a boat in still water is 8km/hr.it can go 15km upstream and 22km downstream in 5hrs.find da speed of the stream.

4.a fast train takes 1 hour less than a slow train for a journey of 200km.if the speed of the slow train is 10km/hr less than that of the fast train.find the speed of the 2 trains.

**(pleez help. in the distance sums im not understanding which value will come 1st n which sine 2 put)**

Dear Student!

Let the present age of Swati be *x *years.

7 years ago,

Varun's age = 5 × (Swati's age)^{2}

∴ Varun's age = 5 × (*x* – 7)^{2}

**Present age of Varun = 5 (****x ****– 7)**^{2}** + 7 **

3 years hence,

Swati's age =

Present age of Swati = 9 years

Present age of Varun =

**3.**

Let the speed of the stream be* x* km/hr.

Speed of the boat upstream = Speed of boat in still water – Speed of the stream

∴ Speed of the boat upstream = (8 – *x*) km/hr

Speed of the boat downstream = Speed of boat in still water + Speed of the stream

∴ Speed of the boat downstream = (8 + *x*) km/hr

Given, Time for upstream journey + Time for downstream journey = 5 hrs

Thus, speed of the stream is 3 km/hr.

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