1. the sum of the ages of a man and his son is 45 years.5 years ago,the product of their ages was 4 times the man's age at that time.
2.7 yrs ago varun's age was 5 times the square of swati's age.3 yrs hence her age will be two fifth of varun's age.find der ages
3.the speed of a boat in still water is 8km/hr.it can go 15km upstream and 22km downstream in 5hrs.find da speed of the stream.
4.a fast train takes 1 hour less than a slow train for a journey of 200km.if the speed of the slow train is 10km/hr less than that of the fast train.find the speed of the 2 trains.
(pleez help. in the distance sums im not understanding which value will come 1st n which sine 2 put)
Let the present age of Swati be x years.
7 years ago,
Varun's age = 5 × (Swati's age)2
∴ Varun's age = 5 × (x – 7)2
Present age of Varun = 5 (x – 7)2 + 7
3 years hence,
Swati's age =
Present age of Swati = 9 years
Present age of Varun =
Let the speed of the stream be x km/hr.
Speed of the boat upstream = Speed of boat in still water – Speed of the stream
∴ Speed of the boat upstream = (8 – x) km/hr
Speed of the boat downstream = Speed of boat in still water + Speed of the stream
∴ Speed of the boat downstream = (8 + x) km/hr
Given, Time for upstream journey + Time for downstream journey = 5 hrs
Thus, speed of the stream is 3 km/hr.
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