Dear Student,

The figure below shows two poles AB and CD such that AB = 6 m and CD = 11 m;

And the distance between the poles = AC = 12 m

So; BE = AC = 12 m and CE = AB = 6 m

And DE = AC - CE = 11 m - 6 m = 5 m

Now considering right triangle BED we have;

(BD)2 = (BE)2+(DE)2 {using Pythagoras theorem}⇒(BD)2 = (12)2+52⇒(BD)2 = 169⇒BD = 169−−−√ = 13BD2 = BE2+DE2 {using Pythagoras theorem}⇒BD2 = 122+52⇒BD2 = 169⇒BD = 169 = 13

Therefore the distance between their tops is 13 m.

Regards