(1 − x 2) dy + xy dx = xy 2 dx Share with your friends Share 0 Global Expert answered this We have,1-x2dy+xy dx=xy2dx⇒1-x2dy=xy2dx-xy dx⇒1-x2dy=xy2-ydx⇒1y2-ydy=x1-x2dxIntegrating both sides, we get∫1y2-ydy=∫x1-x2dx⇒∫1y2-y+14-14dy=∫x1-x2dx⇒∫1y-122-122dy=-12∫-2x1-x2dx⇒12×12log y-12-12y-12+12=-12log 1-x2+log C⇒log y-1y=-12log 1-x2+log C⇒2 log y-1y=-log 1-x2+2 log C⇒log y-12y2=-log1-x2+2 log C⇒log y-12y2+log 1-x2=log C2⇒logy-121-x2y2=log C2⇒y-121-x2y2=C2⇒y-121-x2=y2C2 -1 View Full Answer
