13. in a pentagon, two angles are 40 and 60, and the rest are in the ratio 1:3:7.find the biggest angle of the pentagon.​​

Let ABCDE be the pentagon.Now, A = 40°; B = 60°Let C = x; D = 3x; E = 7xNow, A + B + C + D + E = 540°  Angle sum property40° + 60° + x + 3x + 7x = 540°11x = 540° - 100°11x = 440°x = 40Now, C = 40°Now, D = 3 × 40° = 120°Now, E = 7×40° = 280°So, biggest angle =E =  280°

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The sum of the angles of a pentagon is (5-2)x180=3x180=540degree
Given 
Angle 1=40 Angle 2=60
Sum of the three angles excluding the two angles given=540-(40+60)=440
ratio of the rest of the angles=1:3:7
Measure of the biggest angle=7/(1+3+7) of 440 degree
                                            =7/11*440=280 degree
HENCE, THE MEASURE OF THE BIGGEST ANGLE OF THE PENTAGON IS 280 DEGREE.
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