13. in a pentagon, two angles are 40 and 60, and the rest are in the ratio 1:3:7.find the biggest angle of the pentagon. Share with your friends Share 2 Varun.Rawat answered this Let ABCDE be the pentagon.Now, ∠A = 40°; ∠B = 60°Let ∠C = x; ∠D = 3x; ∠E = 7xNow, ∠A + ∠B + ∠C + ∠D + ∠E = 540° Angle sum property⇒40° + 60° + x + 3x + 7x = 540°⇒11x = 540° - 100°⇒11x = 440°⇒x = 40Now, ∠C = 40°Now, ∠D = 3 × 40° = 120°Now, ∠E = 7×40° = 280°So, biggest angle =∠E = 280° 1 View Full Answer Sayanti Maiti answered this The sum of the angles of a pentagon is (5-2)x180=3x180=540degree Given Angle 1=40 Angle 2=60 Sum of the three angles excluding the two angles given=540-(40+60)=440 ratio of the rest of the angles=1:3:7 Measure of the biggest angle=7/(1+3+7) of 440 degree =7/11*440=280 degreeHENCE, THE MEASURE OF THE BIGGEST ANGLE OF THE PENTAGON IS 280 DEGREE. 2