13) The diagram shows a jar with the dimensions as shown. It contains a liquid of mass 3 kg and density 600 kg m-3. The pressure exerted by the liquid on the base of the jar is
(Take g = 10 m s-2)


A. 1.2 × 103 Pa                    B. 2.4 × 103 Pa
C. 1.2 × 105 Pa                    D. 2.4  × 105 Pa

yes ye s
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not clear
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EVEN I AM NOT CLEAR BUT I HAVE A CALCULATION METHOD BUT ANSWER NOT THERE
pressure=force/unit area
force=mg
f=3*10=30N
​unit area=0.01msq
therefore, pressure=30/0.01
=3000/1
=3000pa
 
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Wow
  • 1
EVEN I AM NOT CLEAR BUT I HAVE A CALCULATION METHOD BUT ANSWER NOT THERE
pressure=force/unit area
force=mg
f=3*10=30N
​unit area=0.01msq
therefore, pressure=30/0.01
=3000/1
=3000pa
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