14.Light of wavelength 5000x10-10m is incident normally on a slit.The first minimum incident of the diffraction pattern is observed to lie at a distance of 5mm from the central maximum on a screen placed at a distance of 3mfrom the slit.Then the width of the slit is -----------

use formula y=XD/d
X= wavelength
Y= distance of first minima
D= distance between slit and screen
d= what is required

d = XDy = 5000×10-10×35×10-3 = 3×10-4 = 0.3 mm

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