15. Find the value of $3^{2^{1^{0^{-1^{-2^{-3}}}}}}$
$$\begin{gathered} \left(a\right) 9^{-8} \\ \left(b\right) 3^{256} \\ \left(c\right) 9 \\ \left(d\right) 3 \end{gathered}$$

Dear Student,

The solution is as under:

$$\begin{gathered} Since, 0^{anything}=0 \\ Hence, 0^{-1^{-2^{-3}}}=0 \\ Thus, \\ =3^{2^{1^{0^{-1^{-2^{-3}}}}}} \\ =3^{2^{1^0}} \left\{as 1^0=1\right\} \\ =3^{2^1} \\ =3^2 \\ =9 \end{gathered}$$

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