19
Answer :
We have equations :
6x + 3y = 6xy ----- ( 1 )
2x + 4y = 5xy ----- ( 2 )
We solve these equations by elimination method , As :
Now we multiply by 3 in equation 2 , and get
6x + 12y = 15xy ----- ( 3 )
Now we subtract equation 1 from equation 3 and get
9y = 9xy
x = 1
And
we multiply 4 in equation 1 and by 3 in equation 2 , and get
24x + 12y = 24xy ----- ( 4 )
6x + 12y = 15xy ----- ( 5 )
Now we subtract equation 5 from equation 4 and get
18x = 9xy
y = 2
So,
x = 1 and y = 2 ( Ans )
We have equations :
6x + 3y = 6xy ----- ( 1 )
2x + 4y = 5xy ----- ( 2 )
We solve these equations by elimination method , As :
Now we multiply by 3 in equation 2 , and get
6x + 12y = 15xy ----- ( 3 )
Now we subtract equation 1 from equation 3 and get
9y = 9xy
x = 1
And
we multiply 4 in equation 1 and by 3 in equation 2 , and get
24x + 12y = 24xy ----- ( 4 )
6x + 12y = 15xy ----- ( 5 )
Now we subtract equation 5 from equation 4 and get
18x = 9xy
y = 2
So,
x = 1 and y = 2 ( Ans )