• 2+2 and 2*2=4
• 3+3/2=9/2 , 3=16/3*3/2=9/2
• 4+4/3=16/3 , 4*4/3
• i need 5 more numbers in this pattern and plz give me a general algebraic form of such pairs
• thankyou

Answer : 

we have 

 1 ) 2  +  2  =  4   and 2 $\times$ 2  =  4

 2 ) 3  + $\frac{3}{2}$  = $\frac{9}{2}$   And 3  $\times$ $\frac{3}{2}$  = $\frac{9}{2}$ 

3 )  4  + $\frac{4}{3}$  = $\frac{16}{3}$  And  4  $\times$ $\frac{4}{3}$  = $\frac{16}{3}$

So we, we can write these numbers as  in this pattern as above given numbers . 

i ) 5 + $\frac{5}{4}$  = $\frac{25}{4}$  And 5 $\times$ $\frac{5}{4}$  = $\frac{25}{4}$

ii )  6 + $\frac{6}{5}$  = $\frac{36}{5}$   And   6  $\times$ $\frac{6}{5}$  = $\frac{36}{5}$ 

iii ) 7  + $\frac{7}{6}$  = $\frac{49}{6}$   And   7  $\times$  $\frac{7}{6}$  = $\frac{49}{6}$

iv ) 8  + $\frac{8}{7}$  = $\frac{64}{7}$   And  8 $\times$$\frac{8}{7}$  = $\frac{64}{7}$

v  ) 9 + $\frac{9}{8}$  = $\frac{81}{8}$   And   9 $\times$ $\frac{9}{8}$  = $\frac{81}{8}$

So,

We can write general algebraic expression for this pattern As : 

x  + $\frac{x}{x - 1}$  = $\frac{x^2}{x - 1}$     And   x  $\times$  $\frac{x}{x - 1}$  = $\frac{x^2}{x - 1}$