2 cells A and B each having e.m.f 1.5v and int. resistances of 1.5ohm and 0.5ohm respectively,are joined in parallel with a 1ohm resistor.calculate currents drawn from the cell and their terminal p.d.'s

Emf of both the cell is 1.5 volt
internal resistance
r₁ = 1.5 ohm
r₂ = 0.5 ohm

As these cells are connected in parallel
their combined resistance
$r = \frac{r_1{r}_2}{r_1+r_2} = 0.375 ohm$
net resistance of the circuit
R = 0.375 + 1 = 1.375 ohm

As voltage in the circuit is same as the one of the emf of the cell then current in the circuit
I = E/R = 1.5/1.375 = 1.09 A

Terminal voltage of the first cell

$$\begin{gathered} V_1 = E - I{r}_{1 }= 1.5- 1.09\times 1.5 \\ {V}_1 = -0.13 volt \\ terminal voltage of the second cell \\ {V}_2 = E-I{r}_2 \\ {V}_{2 } = 0.95 volt \end{gathered}$$