•  2. Expand (x−a)(x−b)
  • If x2 -7x + 12 = (x−a)(x−b)then find a + b. Also find ab
  • Calculate the values of a,b
  • Write the factors of (x2 −7x + 12 )
  • Find the solutions of (x2 −7x + 12)
  • plss answer fastt 

 (xa)(xb)=x(x-b)-a(x-b)=x2-bx-ax+abAnd x2 -7x + 12=x2-3x-4x+12=x(x-3)-4(x-3)=(x-4)(x-3)So, a=4 and b=3 on comparing (x-4)(x-3) with (x-a)(x-b)Hence, a+b=4+3=7and ab=4×3=12 For the solutions equate x2 -7x + 12=0(x-4)(x-3)=0x-4=0 or x-3=0x=4 or x=3

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