2 extremely small charged copper spheres have their centres separated by a distance of 50cm in vacuum.what is the force of repulsion if the two spheres are placed in water? charge on each sphere is 6.5X10 to the power -7 C
Q1 = Q2 = 6.5×10-7C
r = 50 cm = 0.5m
K for vacuum = 1
K for water = 80
By Coulomb’s Law
Thus the sphere will repulse with 
force in water.
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