Login

2) If sinA = root 3/2, find the value of 2cot2A-1.

Sin A = √3/2
Sin A = Sin 60
thus A = 60°
Cot²A = 1/3
According to Question
2Cot²A -1
2(1/3)-1
2/3-1
-1/3

Hope it helps u 💔

  • 8
View Full Answer

sinA = root 3/2

construct a triangle right angled at B.

BC = root 3  and AC = 2 The AB = 1

now , cot = adja/ oppo side = 1 / root 3

thus 2 cot2A - 1

  =  2 . 1 / (root 3)2 - 1

  = 2 - 3/3

  = -1 / 3

  • 11

sin A = root3/2

sin A = 60

A = 60 

then Cot2A = 1/3

then , 2(1/3 ) -1  = -1/3

  • 3
What are you looking for?