22.  A student performed an experiment to verify the conservation of mass.  In this experiment, he mixed 5.3 g of sodium carbonate with 6 g of ethanoic acid.  The products he observed were 2.2 g of CO2 , 0.9g of water and 8.2 g of sodium ethanoate.  Verify the law of conservation of mass.

HI BINAY, I WOULD BE GLAD TO ANSWER YOUR QUESTION...

    5.3g of Sodium Carbonate (Na2CO3)+ 6g of Ethanoic Acid (CH3COOH) = 2.2g of Carbon Dioxide (CO2)+0.9g of Water (H2O)+8.2g of Sodium Ethanoate (CH3COONa)
=> 5.3g+6g = 2.2g+0.9g+8.2g => 11.3g=11.3g.
  Hence, law of conservation of mass is proved...

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Here is a answer

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By Law Of Conservation Of Mass,
Total Mass Of Reactants = Total Mass Of Resultants
5.3+6=2.2+0.9+8.2
11.3 Grams = 11.3 Grams

Hence, Verified

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